Đáp án:
\({{\text{V}}_{{C_2}{H_2}{\text{ dư}}}} = 0,672\;{\text{lít}}\)
\({m_{C{O_2}}} = 10,56{\text{ gam; }}{{\text{m}}_{{H_2}O}} = 2,16{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(2{C_2}{H_2} + 5{O_2}\xrightarrow{{{t^o}}}4C{O_2} + 2{H_2}O\)
Ta có: \({V_{{C_2}{H_2}}} > \frac{2}{5}{V_{{O_2}}} \to {C_2}{H_2}{\text{ dư}}\)
\({V_{{C_2}{H_2}}} = \frac{2}{5}{V_{{O_2}}} = 2,688{\text{ lit}} \to {{\text{V}}_{{C_2}{H_2}{\text{ dư}}}} = 3,36 - 2,688 = 0,672\;{\text{lít}}\)
\({n_{{C_2}{H_2}{\text{ phản ứng}}}} = \frac{{2,688}}{{22,4}} = 0,12{\text{ mol}} \to {{\text{n}}_{C{O_2}}} = 2{n_{{C_2}{H_2}}} = 0,24{\text{ mol; }}{{\text{n}}_{{H_2}O}} = {n_{{C_2}{H_2}}} = 0,12{\text{ mol}}\)
\(\to {m_{C{O_2}}} = 0,24.44 = 10,56{\text{ gam; }}{{\text{m}}_{{H_2}O}} = 0,12.18 = 2,16{\text{ gam}}\)
