Đáp án:
\(\begin{array}{l}
a)\\
CTPT:{C_2}{H_6}\\
b)\\
CTCT:\\
C{H_3} - C{H_3}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
CTPT:{C_x}{H_y}\\
{n_{C{O_2}}} = \dfrac{{8,8}}{{44}} = 0,2mol\\
{n_C} = {n_{C{O_2}}} = 0,2mol\\
{n_{ {H_2}O}} = \dfrac{{5,4}}{{18}} = 0,3mol\\
{n_H} = 2{n_{{H_2}O}} = 0,6mol\\
{n_A} = \dfrac{3}{{30}} = 0,1mol\\
x = \dfrac{{{n_C}}}{{{n_A}}} = \dfrac{{0,2}}{{0,1}} = 3\\
y = \dfrac{{{n_H}}}{{{n_A}}} = \dfrac{{0,6}}{{0,1}} = 6\\
\Rightarrow CTPT:{C_2}{H_6}\\
b)\\
CTCT:\\
C{H_3} - C{H_3}
\end{array}\)