Đáp án:
\({C_9}{H_{12}}\)
Giải thích các bước giải:
\(\begin{array}{l}
{n_{C{O_2}}} = \dfrac{{20,16}}{{22,4}} = 0,9\,mol\\
{n_{{H_2}O}} = \dfrac{{10,8}}{{18}} = 0,6\,mol\\
{n_H} = 2{n_{{H_2}O}} = 1,2\,mol\\
{n_C} = {n_{C{O_2}}} = 0,9\,mol\\
x = \dfrac{{{n_C}}}{{{n_{{C_x}{H_y}}}}} = \dfrac{{0,9}}{{0,1}} = 9\\
y = \dfrac{{{n_H}}}{{{n_{{C_x}{H_y}}}}} = \dfrac{{1,2}}{{0,1}} = 12\\
\Rightarrow CTPT:{C_9}{H_{12}}
\end{array}\)