$Ankan:C_{n}H_{2n+2}$
$C_{n}H_{2n+2} \to nCO_{2}$
$\frac{0,1}{n}$ 0,1
$nCO_{2}=\frac{2,24}{22,4}=0,1$
$MAnkan=\frac{1,45}{\frac{0,1}{n}}$
⇔$14n+2=\frac{1,45}{\frac{0,1}{n}}$
⇔$n=4$
⇒$CTPT:C_{4}H_{10}$
CTCT:
+$CH_{3}-CH_{2}-CH_{2}-CH_{3}$: butan
+$CH_{3}-CH(CH_{3})-CH_{3}$: propan