Đáp án:
Giải thích các bước giải:
$d_{A/CH4}$ =$11,75.16$=188g/mol$
$n_{CO2}$ =$\frac{2,016}{22,4}$ =$0,09mol$
Bảo toàn C:
⇒ $n_{C}$=$0,09mol$
$m_{C}$=$0,09.12$=$1,08g$
$n_{H2O}$=$\frac{1,44}{18}$=$0,08mol$
Bảo toàn H:
⇒ $n_{H}$=$0,08mol$
⇒ $m_{H}$=$0,08.2$=$0,16g$
⇒ $m_{O}$=$1,88-1.08-0,16$=$0,64g$
=>CTTQ:$CxHyOz$
$x:y:z$=$\frac{1,08}{12}$: $\frac{0,16}{1}$: $\frac{0,64}{16}$
=$0,09:0,16:0,04$
=$2,25:4:1$
=$9:16:4$
=>CTDGN: $C9H16O4$
CTPT: $(C9H16O4)n$=$188$
$(12.9+1.16+16.4)n$=$188$
$188n$=$188$
⇒$n$=$1$
⇒$C9H16O4$