Đáp án:
\(\begin{array}{l}
a)\\
CTPT:{C_3}{H_8}\\
b)\\
C{H_3} - C{H_2} - C{H_3}(propan)
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
CTPT:{C_x}{H_y}\\
{n_{C{O_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3mol\\
{n_{{H_2}O}} = \dfrac{{7,2}}{{18}} = 0,4mol\\
{n_C} = {n_{C{O_2}}} = 0,3mol\\
{n_H} = 2{n_{{H_2}O}} = 0,8mol\\
\dfrac{x}{y} = \dfrac{{{n_C}}}{{{n_H}}} = \dfrac{{0,3}}{{0,8}} = \dfrac{3}{8}\\
\Rightarrow CTPT:{C_3}{H_8}\\
b)\\
C{H_3} - C{H_2} - C{H_3}(propan)
\end{array}\)