Đáp án:
$\%C$=100-0,5-1,5=98%
$C$ + $O_{2}$ → $CO_{2}$
1960 1960
$S$ + $O_{2}$ → $SO_{2}$
3,75 3,75
m$C$=24.98%=23,52g
n$C$=$\frac{23,52.100}{12}$ =1960
m$S$=24.0,5%=0,12
n$S$=$\frac{0,12.1000}{32}$ =3,75
V$CO_{2}$=1960.22,4=43904lit
V$SO_{2}$ =3,75.22,4=84lit