`a+b,` $n_{Zn}=\dfrac{m}{M}=\dfrac{20,25}{65+16}=0,25(mol)$
$ZnO+H_2→Zn+H_2O$
`1` `:` `1` `:` `1` `:` `1`
$0,25 → 0,25$
$m_{Zn}=n_{Zn}.M_{Zn}=0,25.65=16,25(g)$
`c,` $n_{HCl}=\dfrac{m}{M}=\dfrac{7,3}{1+35,5}=0,2(mol)$
$Zn+2HCl→ZnCl_2+H_2$
`1` `:` `2` `:` `1` `:` `1`
$\dfrac{0,25}{1}>\dfrac{0,2}{2}$
$⇒Zn$ dư
$⇒n_{ZnCl_2}=0,2.1:2=0,1(mol)$
$⇒m_{ZnCl_2}=n.M=0,1.(65+35,5.2)=13,6(g)$