Đáp án:
`10)x³-8`
`11)x³+64`
`12)x³-27y³`
`13)x^6-1/27`
Giải thích các bước giải:
`10)(x-2)(x²+2x+4)`
`=(x-2)(x²+x.2+2²)`
`=x³-2³`
`=x³-8`
`11)(x+4)(x²-4x+16)`
`=(x+4)(x²-x.4+2²)`
`=x³+4³`
`=x³+64`
`12)(x-3y)(x²+3xy+9y²)`
`=(x-3y)[x²+x.3y+(3y)²]`
`=x³-(3y)³`
`=x³-27y³`
`13)(x²-1/3)(x^4+1/3x²+1/9)`
`=(x²-1/3)[(x^2)^2+x². 1/3+(1/3)^2]`
`=(x^2)^3-(1/3)^3`
`=x^6-1/27`
