(1 – x)(x + 2) = 0
(=)\(\left[ \begin{array}{l}1-x=0\\x+2=0\end{array} \right.\) (=)\(\left[ \begin{array}{l}x=1\\x=-2\end{array} \right.\)
(2x – 2)(6 + 3x)(3x + 2) = 0
1)2x-2=0=)2x=2=)x=1
2)6+3x=0=)3x=-6=)x=-2
3)3x+2=0=)3x=-2=)x=-$\frac{2}{3}$
(5x – 5)(3x + 2)(8x + 4)(x2 – 5) = 0
1)5x-5=0=)5x=5=)x=1
2)3x+2=0=)3x=-2=)x=-$\frac{2}{3}$
3)8x+4=0=)8x=-4=)x=-$\frac{1}{2}$
4)x²-5=0=)x²=5=)x=±√5
đoạn sau mình ko hiểu lắm