Đáp án:
Giải thích các bước giải:
`(-153,6)/y + 3y = 4,8`
`<=> −153,6 + 3yy = 4,8y`
`<=> −153,6 + 3y^2 = 4,8y`
`<=> −153,6 + 3y^2 − 4,8y = 0`
`<=> 3y^2 − 4,8y − 153,6 = 0`
`<=> y=\frac{−(−4,8)±\sqrt{(−4,8)^2−4.3(−153,6)}}{2×3}`
`<=> y=\frac{−(−4,8)±\sqrt{23,04−12(−153,6)}}{2×3}`
`<=> y=\frac{−(−4,8)±\sqrt{23,04+1843,2}}{2×3}`
`<=> y=\frac{−(−4,8)±\sqrt{1866,24}}{2×3}`
`<=> y=\frac{4,8±\frac{216}{5}}{6}`
`<=>`\(\left[ \begin{array}{l}y=\frac{4,8+\frac{216}{5}}{6}\\y=\frac{4,8-\frac{216}{5}}{6}\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}y=\frac{48}{6}\\y=\frac{-\frac{216}{5}}{6}\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}y=8\\y=-\frac{23}{5}=-6\frac{2}{5}=-6,4\end{array} \right.\)
Vậy `y∈{8;-6,4}`
