Đáp án:
$\text{In}\Bigg|\dfrac{x+1}{x+2}\Bigg|+C$
Giải thích các bước giải:
$\displaystyle\int\dfrac{1}{(x+1)(x+2)} dx$
$=\displaystyle\int\bigg(\dfrac 1{x+1}-\dfrac 1{x+2}\bigg)dx$
$=\text{In} |x+1|-\text{In}|x+2|+C$
$=\text{In}\Bigg|\dfrac{x+1}{x+2}\Bigg|+C$