Đáp án đúng: C Ta có: $ C=\underset{x\to -\infty }{\mathop{\lim }}\,\dfrac{\left| x \right|\sqrt{4-\dfrac{2}{{}{ x ^ 2 }}}+x\sqrt[3]{1+\dfrac{1}{{}{ x ^ 3 }}}}{\left| x \right|\sqrt{1+\dfrac{1}{{}{ x ^ 2 }}}-x}$
$=\underset{x\to -\infty }{\mathop{\lim }}\,\dfrac{-\sqrt{4-\dfrac{2}{{}{ x ^ 2 }}}+\sqrt[3]{1+\dfrac{1}{{}{ x ^ 3 }}}}{-\sqrt{1+\dfrac{1}{{}{ x ^ 2 }}}-1}=\dfrac{-2+1}{-2}=\dfrac{1}{2} $