a) $\frac{11(8-3)}{11}$ = $\frac{11.5}{11}$ = 5
b)$\frac{12(12-13)}{12(1+3)}$ = $\frac{-11}{4}$
c) $\frac{7(6-4)}{7.3}$ = $\frac{2}{3}$
d)$\frac{7}{10^2(9-2)}$ = $\frac{1}{10^2}$
e) $\frac{3(-7-8)}{3(2-5)}$ = $\frac{-15}{-3}$ = 5
f) $\frac{17(-13+2)}{11(2-19)}$ = 1
