`(2x+3)(-x+1)>0`
`<=>`\(\left[ \begin{array}{l}\begin{cases}2x+3<0\\-x+1<0\end{cases}\\\begin{cases}2x+3>0\\-x+1>0\end{cases}\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}\begin{cases}x<-\dfrac32\\x>1\end{cases}\ \ (\rm KTM)\\\begin{cases}x>-\dfrac32\\x<1\end{cases}\ \ (\rm TM)\end{array} \right.\)
`<=>-3/2<x<1`
Vậy `x\in (-3/2;1)`