Đáp án:
$2+$$\dfrac{3(x+1)}{8}$ $< 3-$$\dfrac{(x-1)}{4}$
$⇔$ $\dfrac{16+3(x+1)}{8}$ $<$ $\dfrac{12-(x-1)}{4}$
$⇔$ $\dfrac{16+3x+3}{8}$ $<$ $\dfrac{12-x+1}{4}$
$⇔$ $\dfrac{19+3x}{8}$ $<$ $\dfrac{13-x}{4}$
$⇔ 19+3x<2(13-x)$
$⇔ 19+3x<26-2x$
$⇔ 19+3x-26+2x<0$
$⇔ 5x-7<0$
$⇔ 5x<7$
$⇔ x<1,4$
BẠN THAM KHẢO NHA!!!