Giải bất phương trình: \(\frac{{3{x^2} - 8x - 3}}{{2x - 1}} \ge 0\).
A.\(x \in \left[ { - \frac{1}{3};\frac{1}{2}} \right) \cup \left[ {3; + \infty } \right)\)
B.\(x \in \left( { - \infty ;\frac{1}{2}} \right) \cup \left[ {3; + \infty } \right)\)
C.\(x \in \left( { - \infty ; - \frac{1}{3}} \right] \cup \left( {\frac{1}{2};3} \right]\)
D.\(x \in \left( { - \infty ; - \frac{1}{3}} \right] \cup \left( {\frac{1}{2}; + \infty } \right)\)