Đáp án:
\(\begin{array}{l}
a.\frac{5}{3} > x\\
b.x > \frac{3}{2}\\
c.x > - \frac{5}{2}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.2\left( {5 - 3x} \right) > 0\\
\to 5 - 3x > 0\\
\to 5 > 3x\\
\to \frac{5}{3} > x\\
b.\frac{{x - 1}}{{2x - 3}} > \frac{1}{2}\\
\to \frac{{2x - 2 - 2x + 3}}{{2\left( {2x - 3} \right)}} > 0\\
\to \frac{1}{{2\left( {2x - 3} \right)}} > 0\\
\to 2x - 3 > 0\\
\to x > \frac{3}{2}\\
c.\left( {{x^2} + 1} \right)\left( {2x + 5} \right) > 0\\
\to 2x + 5 > 0\left( {do:{x^2} + 1 > 0\forall x \in R} \right)\\
\to x > - \frac{5}{2}
\end{array}\)
