e) $\dfrac{5}{2}-|\dfrac{1}{2}-x|=6$
$|\dfrac{1}{2}-x|=\dfrac{5}{2}-6=\dfrac{-7}{2}$
\(⇒\left[ \begin{array}{l}\dfrac{1}{2}-x=2\\\dfrac{1}{2}-x=-2\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{1}{2}-2⇒x=\dfrac{-3}{2}\\x=\dfrac{1}{2}+2⇒x=\dfrac{5}{2}\end{array} \right.\)
f) Theo đề bài:
⇒ TH1:
$x:(-\dfrac{5}{6})-\dfrac{3}{4}=2$
$x.\dfrac{-6}{5}=2+\dfrac{3}{4}$
$x.\dfrac{-6}{5}=\dfrac{11}{4}$
$⇒x=\dfrac{11}{4}:\dfrac{-6}{5}=\dfrac{11}{4}.\dfrac{-5}{6}=-\dfrac{55}{24}$
⇒ TH2:
$x:(-\dfrac{5}{6})-\dfrac{3}{4}=-2$
$x.\dfrac{-6}{5}=-2+\dfrac{3}{4}$
$x.\dfrac{-6}{5}=\dfrac{-5}{4}$
$⇒x=\dfrac{-5}{4}:\dfrac{-6}{5}=\dfrac{-5}{4}.\dfrac{-5}{6}=\dfrac{25}{24}$
