Đáp án + Giải thích các bước giải:
a)
`1/3\sqrt{9x-9}-2\sqrt{x-1}+8\sqrt{(4x-4)/25}=11(x\ge1)`
`=>1/3\sqrt{9(x-1)}-2\sqrt{x-1}+8(\sqrt{4(x-1)})/5=11`
`=>1/3 .3\sqrt{x-1}-2\sqrt{x-1}+8.(2\sqrt{x-1})/5=11`
`=>\sqrt{x-1}-2\sqrt{x-1}+16/5\sqrt{x-1}=11`
`=>11/5\sqrt{x-1}=11`
`=>\sqrt{x-1}=5`
`=>x-1=25`
`=>x=26(tm)`
b)
`2x-5\sqrtx+3=0(x\ge0)`
`=>2x-2\sqrtx-3\sqrtx+3=0`
`=>2\sqrtx(\sqrtx-1)-3(\sqrtx-1)=0`
`=>(\sqrtx-1)(2\sqrtx-3)=0`
`=>\sqrtx-1=0` hoặc `2\sqrtx-3=0`
`=>\sqrtx=1` hoặc `2\sqrtx=3`
`=>x=1` hoặc `\sqrtx=3/2`
`=>x=1(tm)` hoặc `x=9/4(tm)`
Vậy `x\in{1;9/4}`
