Bạn tham khảo:
a) $x( x - 4 ) + 3x - 12 = 0$
$⇔ x( x - 4 ) + 3 ( x - 4) = 0$
$⇔ ( x - 4 )( x + 3 ) = 0 $
⇔ \(\left[ \begin{array}{l}x=4\\x=-3\end{array} \right.\)
b) $( x - 7 )( 2x + 8 ) = 0 $
$⇔ 2( x - 7 ) ( x + 4 ) = 0 $
⇔ \(\left[ \begin{array}{l}x=7\\x=-4\end{array} \right.\)