Em tham khảo nha:
\(\begin{array}{l}
a)\\
C{H_3} - C{H_2} - OH\\
C{H_3}COOH\\
b)\\
C{H_3}COOH + {C_2}{H_5}OH \xrightarrow{H_2SO_4,t^0} C{H_3}COO{C_2}{H_5} + {H_2}O\\
Z:etyl\,{\rm{ax}}etat\\
c)\\
C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O(1)\\
C{H_3}COO{C_2}{H_5} + NaOH \to C{H_3}COONa + {C_2}{H_5}OH(2)\\
2{C_2}{H_5}OH + 2Na \to 2{C_2}{H_5}ONa + {H_2}\\
{n_{{H_2}}} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
{n_{{C_2}{H_5}OH}} = 2{n_{Na}} = 0,2\,mol\\
{n_{NaOH}} = 0,3 \times 1 = 0,3\,mol\\
{n_{NaOH(2)}} = {n_{{C_2}{H_5}OH}} = 0,2\,mol\\
{n_{C{H_3}COO{C_2}{H_5}}} = {n_{{C_2}{H_5}OH}} = 0,2\,mol\\
{n_{NaOH(1)}} = 0,3 - 0,2 = 0,1\,mol\\
{n_{C{H_3}COOH}} = {n_{NaOH(1)}} = 0,1\,mol\\
m = 0,1 \times 60 + 0,2 \times 88 = 23,6g
\end{array}\)