ĐKXĐ: x khác ±5
Có: (2x-1)/(x+5) - 2/(x-5) = (2x²+2x)/(x²-25)
⇔ (2x-1)(x-5)/(x²-25) - 2(x+5)/(x²-25) = (2x²+2x)/(x²-25)
⇔(2x²-11x+5)/(x²-25) - (2x+10)/(x²-25)= (2x²+2x)/(x²-25)
⇔(2x²-13x-5)/(x²-25)=(2x²+2x)/(x²-25)
⇔2x²-13x-5=2x²+2x
⇔15x=-5
⇔x=-1/3(TMĐK)