Giải thích các bước giải:
Ta có $2x-3y=5\to x=\dfrac{5+3y}{2}$
$\to \dfrac{1}{3x-2y}+\dfrac{1}{x+y+1}=\dfrac{6}{5}$
$\to \dfrac{1}{3\dfrac{5+3y}{2}-2y}+\dfrac{1}{\dfrac{5+3y}{2}+y+1}=\dfrac{6}{5}$
$\to \dfrac{2}{15+5y}+\dfrac{2}{5y+7}=\dfrac{6}{5}$
$\to y=-1\to x=1,y=\dfrac{-41}{15}\to x=\dfrac{-49}{5}$