Đáp án:
20,8695 kg
Giải thích các bước giải:
\(\begin{array}{l}
V{C_2}{H_5}OH = \dfrac{{V{\rm{dd}} \times Dr}}{{100}} = \dfrac{{10 \times 8}}{{100}} = 0,8l = 800ml\\
m{C_2}{H_5}OH = D \times V = 0,8 \times 800 = 640g\\
n{C_2}{H_5}OH = \dfrac{m}{M} = \dfrac{{640}}{{46}} = \dfrac{{320}}{{23}}\,mol\\
{C_2}{H_5}OH + {O_2} \to C{H_3}COOH + {H_2}O\\
nC{H_3}COOH = n{C_2}{H_5}OH = \dfrac{{320}}{{23}}\,mol\\
mC{H_3}COOH = n \times M = \dfrac{{320}}{{23}} \times 60 = 834,78g\\
m{\rm{dd}} = \dfrac{{mct \times 100}}{{C\% }} = \frac{{834,78 \times 100}}{4} = 20869,5g = 20,8695kg
\end{array}\)
