Đáp án:
\({\text{[}}{H^ + }{\text{]}} = 2M\)
Giải thích các bước giải:
Ta có:
\({m_{{H_2}S{O_4}}} = 400.49\% = 196{\text{ gam}}\)
\( \to {n_{{H_2}S{O_4}}} = \frac{{196}}{{96}} = 2{\text{ mol}}\)
\({H_2}S{O_4}\xrightarrow{{}}2{H^ + } + S{O_4}^{2 - }\)
\( \to {n_{{H^ + }}} = 2{n_{{H_2}S{O_4}}} = 2.2 = 4{\text{ mol}}\)
\( \to {\text{[}}{H^ + }{\text{]}} = \frac{{{n_{{H^ + }}}}}{{{V_{dd\;{\text{A}}}}}} = \frac{4}{2} = 2M\)
