Đáp án:
$\begin{array}{l}
d)Theo\,Viet:\left\{ \begin{array}{l}
{x_1} + {x_2} = 3 - m\\
{x_1}{x_2} = - 2m + 2
\end{array} \right.\\
2{x_1} + {x_2} = 3\\
\Rightarrow {x_2} = 3 - 2{x_1}\\
\Rightarrow {x_1} + 3 - 2{x_1} = 3 - m\\
\Rightarrow {x_1} = m\\
\Rightarrow {x_2} = 3 - 2m\\
Thay\,{x_1} = m;{x_2} = 3 - 2m\\
\Rightarrow {x_1}.{x_2} = m.\left( {3 - 2m} \right) = - 2m + 2\\
\Rightarrow 3m - 2{m^2} + 2m - 2 = 0\\
\Rightarrow 2{m^2} - 5m + 2 = 0\\
\Rightarrow \left( {2m - 1} \right)\left( {m - 2} \right) = 0\\
\Rightarrow \left[ \begin{array}{l}
m = \dfrac{1}{2}\\
m = 2
\end{array} \right.
\end{array}$
Vậy m=1/2 hoặc m=2.
