Em tham khảo nha :
\(\begin{array}{l}
d)\\
A{l_4}{C_3} + 12{H_2}O \to 4Al{(OH)_3} + 3C{H_4}\\
2C{H_4} \xrightarrow{t^0} {C_2}{H_2} + 2{H_2}\\
{C_2}{H_2} + HCl \xrightarrow{t^0,Áp suất , xt} {C_2}{H_3}Cl\\
n{C_2}{H_3}Cl \to {( - C{H_2} - CHCl - )_n}
\end{array}\)
\(\begin{array}{l}
e)\\
Ca{C_2} + 2{H_2}O \to {C_2}{H_2} + Ca{(OH)_2}\\
2{C_2}{H_2} \xrightarrow{t^0,CuCl} {C_4}{H_4}\\
{C_4}{H_4} + {H_2} \xrightarrow{t^0,Ni} {C_4}{H_6}\\
nC{H_2} = CH - CH = C{H_2} \xrightarrow{t^0,Na} {( - C{H_2} - CH = CH - C{H_2} - )_n}
\end{array}\)
\(\begin{array}{l}
f)\\
2C{H_4} \xrightarrow{t^0} {C_2}{H_2} + 2{H_2}\\
2{C_2}{H_2} \xrightarrow{t^0,CuCl} {C_4}{H_4}\\
{C_4}{H_4} + 3{H_2} \xrightarrow{t^0} {C_4}{H_{10}}\\
2{C_4}{H_{10}} + 13{O_2} \xrightarrow{t^0} 8C{O_2} + 10{H_2}O
\end{array}\)
