Đáp án:
d) \(\left[ \begin{array}{l}
x = 0\\
x = 6
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
b)DK:x \ne 4\\
\dfrac{{2.14 - 6\left( {x + 2} \right)}}{{6\left( {x - 4} \right)}} = \dfrac{{ - 3.3 - 5\left( {x - 4} \right)}}{{6\left( {x - 4} \right)}}\\
\to 28 - 6x - 12 = - 9 - 5x + 20\\
\to x = 5\\
d)DK:x \ne \pm 4\\
\dfrac{{2x\left( {x - 4} \right) - 4x}}{{\left( {x - 4} \right)\left( {x + 4} \right)}} = 0\\
\to 2{x^2} - 8x - 4x = 0\\
\to 2{x^2} - 12x = 0\\
\to 2x\left( {x - 6} \right) = 0\\
\to \left[ \begin{array}{l}
x = 0\\
x = 6
\end{array} \right.
\end{array}\)
