Đáp án:
Giải thích các bước giải:
$b.\sqrt{7-4\sqrt{3}}+\sqrt{4-2\sqrt{3}}$
$=\sqrt{4-2.2.\sqrt{3}+3}+\sqrt{3-2.\sqrt{3}.1}$
$=\sqrt{4}-\sqrt{3}+\sqrt{3}-1$
$=2-1=1$
$c,\sqrt{11-6\sqrt{2}}+\sqrt{11+6\sqrt{2}}$
$=\sqrt{9}-\sqrt{2}+\sqrt{9}+\sqrt{2}$
$=2\sqrt{9}=2.3=6$
$d,\sqrt{302-20\sqrt{6}}+\sqrt{203-20\sqrt{6}}$
$=\sqrt{302-2.10.\sqrt{6}}+\sqrt{203-2.10.\sqrt{6}}$
$=\sqrt{300-2.10\sqrt{3}.\sqrt{2}+2}+\sqrt{200-2.10\sqrt{2}.\sqrt{3}+3}$
$=10\sqrt{3}-\sqrt{2}+10\sqrt{2}-\sqrt{3}$
$=9\sqrt{3}+9\sqrt{2}$
$e,\sqrt{601-20\sqrt{6}}-\sqrt{154-20\sqrt{6}}$
$=\sqrt{600-2.10\sqrt{6}.1+1}-\sqrt{150-2.5\sqrt{6}.4+2}$
$=10\sqrt{6}-1-5\sqrt{6}+2$
$=5\sqrt{6}+1$
Chúc bạn học tốt.
