A =($\frac{√x(√x+1)-(x+2)}{√x +1}$ ):($\frac{Vx(√x -1)+√x-4)}{(√x+1)(√x-1)}$ )
=($\frac{(x+√x-x+2)}{√x +1}$ :($\frac{x-√x+√x -4}{(√x+1)(√x-1)}$ )
=$\frac{√x +2}{√x+1}$ :$\frac{x-4}{(√x+1)(√x-1)}$
=$\frac{√x+2}{√x+1}$ .$\frac{(√x+1)(√x-1)}{(√x+2)(√x-2)}$
=$\frac{√x -1}{√x-2}$