Đáp án:
2) y=3; x=0
Giải thích các bước giải:
\(\begin{array}{l}
2)DK:x \ne - 1;y \ne 2\\
\left\{ \begin{array}{l}
\dfrac{{3\left( {y - 2} \right) - 4\left( {x + 1} \right) + \left( {x + 1} \right)\left( {y - 2} \right)}}{{\left( {x + 1} \right)\left( {y - 2} \right)}} = 0\\
x + y - 1 = 2\left( {x + 1} \right)\left( {y - 2} \right)
\end{array} \right.\\
\to \left\{ \begin{array}{l}
3y - 6 - 4x - 4 + xy - 2x + y - 2 = 0\\
x + y - 1 = 2\left( {xy - 2x + y - 2} \right)
\end{array} \right.\\
\to \left\{ \begin{array}{l}
- 6x + 4y + xy = 12\\
5x - y - 2xy = - 3
\end{array} \right.\\
\to \left\{ \begin{array}{l}
- 12x + 8y + 2xy = 24\\
5x - y - 2xy = - 3
\end{array} \right.\\
\to \left\{ \begin{array}{l}
- 7x + 7y = 21\\
5x - y - 2xy = - 3
\end{array} \right.\\
\to \left\{ \begin{array}{l}
- x + y = 3\\
5x - y - 2xy = - 3
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = y - 3\\
5\left( {y - 3} \right) - y - 2\left( {y - 3} \right).y = - 3\left( 1 \right)
\end{array} \right.\\
\left( 1 \right) \to 5y - 15 - y - 2\left( {{y^2} - 3y} \right) = - 3\\
\to - 2{y^2} + 10y - 12 = 0\\
\to \left[ \begin{array}{l}
y = 3\\
y = 2\left( l \right)
\end{array} \right. \to x = 0
\end{array}\)
( câu 1 thiếu dấu "=" bạn )
