Giải hệ phương trình: \(\left\{ \begin{array}{l}2{\left( {x - 2} \right)^2} + \frac{1}{{\sqrt {y + 5} }} = 3\\{\left( {x - 2} \right)^2} - \frac{2}{{\sqrt {y + 5} }} = - 1\end{array} \right..\)
A.\(\left( {x;y} \right) \in \left\{ {\left( {3; - 1} \right);\left( {1; - 1} \right)} \right\}\)
B.\(\left( {x;y} \right) \in \left\{ {\left( {2; - 1} \right);\left( {1; - 1} \right)} \right\}\)
C.\(\left( {x;y} \right) \in \left\{ {\left( {3; - 4} \right);\left( {1; - 4} \right)} \right\}\)
D.\(\left( {x;y} \right) \in \left\{ {\left( {2; - 4} \right);\left( {1; - 4} \right)} \right\}\)
A.\(\left( {x;y} \right) \in \left\{ {\left( {3; - 1} \right);\left( {1; - 1} \right)} \right\}\)
B.\(\left( {x;y} \right) \in \left\{ {\left( {2; - 1} \right);\left( {1; - 1} \right)} \right\}\)
C.\(\left( {x;y} \right) \in \left\{ {\left( {3; - 4} \right);\left( {1; - 4} \right)} \right\}\)
D.\(\left( {x;y} \right) \in \left\{ {\left( {2; - 4} \right);\left( {1; - 4} \right)} \right\}\)
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Hóa Học lớp 12
