Giải hệ phương trình: \(\left\{ \begin{array}{l}xy + 3{y^2} + x = 3 & \left( 1 \right)\\{x^2} + xy - 2{y^2} = 0 & \left( 2 \right)\end{array} \right.\).
A.\(\left( {x;y} \right) \in \left\{ {\left( { - 1; - 1} \right);\left( {\frac{3}{4};\frac{3}{4}} \right);\left( {2; - 1} \right);\left( { - 6;3} \right)} \right\}.\)
B.\(\left( {x;y} \right) \in \left\{ {\left( { 1; 1} \right);\left( { - \frac{3}{4}; - \frac{3}{4}} \right);\left( {2; - 1} \right);\left( { - 6;3} \right)} \right\}.\)
C.\(\left( {x;y} \right) \in \left\{ {\left( { 1; 1} \right);\left( {\frac{3}{4};\frac{3}{4}} \right);\left( {2; - 1} \right);\left( { - 6;3} \right)} \right\}.\)
D.\(\left( {x;y} \right) \in \left\{ {\left( { - 1; - 1} \right);\left( { - \frac{3}{4}; - \frac{3}{4}} \right);\left( {2; - 1} \right);\left( { - 6;3} \right)} \right\}.\)

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