Giải hệ phương trình: \( \left \{ \begin{array}{l}{x^2} + 4{y^2} = 2 \ \(x - 2y)(1 - 2xy) = 4 \end{array} \right. \).
A.\((x;y) = \left( { - 1;\,\frac{1}{2}} \right).\)
B.\((x;y) = \left( { - 1; - \frac{1}{2}} \right).\)
C.\((x;y) = \left( {1;\,\frac{1}{2}} \right).\)
D.\((x;y) = \left( {1; - \frac{1}{2}} \right).\)
A.\((x;y) = \left( { - 1;\,\frac{1}{2}} \right).\)
B.\((x;y) = \left( { - 1; - \frac{1}{2}} \right).\)
C.\((x;y) = \left( {1;\,\frac{1}{2}} \right).\)
D.\((x;y) = \left( {1; - \frac{1}{2}} \right).\)
Loga
Hóa Học lớp 12
