Giải hệ phương trình: \( \left \{ \begin{array}{l}{x^2} + {y^2} = 2 \ \ \left( {x + 2y} \right) \left( {2 + 3{y^2} + 4xy} \right) = 27 \end{array} \right.. \)
A.\(\left( {x;y} \right) = \left\{ {\left( {1;2} \right)\,\,;\,\,\left( {\frac{1}{5};\frac{7}{5}} \right)} \right\}\)
B.\(\left( {x;y} \right) = \left\{ {\left( {1;2} \right)\,\,;\,\,\left( {\frac{2}{5};\frac{7}{5}} \right)} \right\}\)
C.\(\left( {x;y} \right) = \left\{ {\left( {2;1} \right)\,\,;\,\,\left( {\frac{2}{5};\frac{7}{5}} \right)} \right\}\)
D.\(\left( {x;y} \right) = \left\{ {\left( {1;1} \right)\,\,;\,\,\left( {\frac{1}{5};\frac{7}{5}} \right)} \right\}\)
A.\(\left( {x;y} \right) = \left\{ {\left( {1;2} \right)\,\,;\,\,\left( {\frac{1}{5};\frac{7}{5}} \right)} \right\}\)
B.\(\left( {x;y} \right) = \left\{ {\left( {1;2} \right)\,\,;\,\,\left( {\frac{2}{5};\frac{7}{5}} \right)} \right\}\)
C.\(\left( {x;y} \right) = \left\{ {\left( {2;1} \right)\,\,;\,\,\left( {\frac{2}{5};\frac{7}{5}} \right)} \right\}\)
D.\(\left( {x;y} \right) = \left\{ {\left( {1;1} \right)\,\,;\,\,\left( {\frac{1}{5};\frac{7}{5}} \right)} \right\}\)
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Hóa Học lớp 12
