Đáp án:
$a. \frac{2}{3}$
$b. 2048$
$c. - 3$
Giải thích các bước giải:
$a. \frac{16^{5}.2^{8}.9}{8^{5}.4^{6}.27}$
$= \frac{(2^{4})^{5}.2^{8}.9}{(2^{3})^{5}.(2^{2})^{6}.9.3}$
$= \frac{2^{20}.2^{8}}{2^{15}.2^{12}.3}$
$= \frac{2^{28}}{2^{27}.3}$
$= \frac{2}{3}$
$b. \frac{(-16)^{5}.(-2)^{18}}{(-8)^{5}.(-4)^{6}}$
$= \frac{-(2^{4})^{5}.2^{18}}{-(2^{3})^{5}.(2^{2})^{6}}$
$= \frac{2^{20}.2^{18}}{2^{15}.2^{12}}$
$= \frac{2^{38}}{2^{27}}$
$= 2^{11}$
$= 2048$
$c. \frac{(-2)^{11}.9^{2}}{6^{3}.16^{2}}$
$= \frac{-2^{11}.(3^{2})^{2}}{(2.3)^{3}.(2^{4})^{2}}$
$= \frac{-2^{11}.3^{4}}{2^{3}.3^{3}.2^{8}}$
$= \frac{-2^{11}.3^{4}}{2^{11}.3^{3}}$
$= - 3$
