Đáp án:
\(\left\{ \begin{array}{l}
x = 0\\
y = \frac{5}{2}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
DK:x \ne - 1;y \ne 2\\
\left\{ \begin{array}{l}
\frac{{x + 2}}{{x + 1}} + \frac{2}{{y - 2}} = 6\\
\frac{{10}}{{x + 1}} - \frac{2}{{y - 2}} = 6
\end{array} \right.\\
\to \left\{ \begin{array}{l}
\frac{{x + 2}}{{x + 1}} + \frac{{10}}{{x + 1}} = 12\\
\frac{{x + 2}}{{x + 1}} + \frac{2}{{y - 2}} = 6
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x + 2 + 10 = 12x + 12\\
\frac{{x + 2}}{{x + 1}} + \frac{2}{{y - 2}} = 6
\end{array} \right.\\
\to \left\{ \begin{array}{l}
11x = 0\\
\frac{{x + 2}}{{x + 1}} + \frac{2}{{y - 2}} = 6
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = 0\\
y = \frac{5}{2}
\end{array} \right.\left( {TM} \right)
\end{array}\)
