Em tham khảo nha :
\(\begin{array}{l}
1)\\
4K + {O_2} \to 2{K_2}O\\
2Al + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}\\
3AgN{O_3} + N{a_3}P{O_4} \to A{g_3}P{O_4} + 3NaN{O_3}\\
2)\\
a)\\
{n_{C{O_2}}} = \dfrac{{4,4}}{{44}} = 0,1mol\\
{V_{C{O_2}}} = 0,1 \times 22,4 = 2,24l\\
b)\\
{m_{FeO}} = 0,25 \times 72 = 18g\\
3)\\
\% Ca = \dfrac{{{M_{Ca}}}}{{{M_{Ca{C_2}}}}} \times 100\% = \dfrac{{40}}{{64}} \times 100\% = 62,5\% \\
\% C = 100 - 62,5 = 37,5\% \\
4)\\
{N_{N{H_3}}} = n \times {N_A} = 0,6 \times 6 \times {10^{23}} = 3,6 \times {10^{23}}\text{(Phân tử )}
\end{array}\)