Đáp án:
Dưới
Giải thích các bước giải:
$|x+1|^{2016}+|x+2|^{2017}=1$
$⇒TH1$:\(\left[ \begin{array}{l}|x+1|^{2016}=1\\|x+2|^{2017}=0\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}|x+1|=±1\\|x+2|=0\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}x∈{-2,0}\\x=-2\end{array} \right.\)
$⇒TH2:$\(\left[ \begin{array}{l}|x+1|^{2016}=0\\|x+2|^{2017}=1\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}|x+1|=0\\|x+2|=±1\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}x=-1\\x∈{-1,-3}\end{array} \right.\)
