Đáp án:
Giải thích các bước giải:
( 3x - $\frac{1}{2}$ ) ( $\frac{-2}{3}$ x+1 ) =0
=> \(\left[ \begin{array}{l}3x- \frac{1}{2}=0\\\frac{-2}{3}x+1 =0\end{array} \right.\)
=> \(\left[ \begin{array}{l}3x= \frac{1}{2}\\\frac{-2}{3}x =-1\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=\frac{1}{6} \\x=\frac{3}{2} \end{array} \right.\)