Giải phương trình: $3\cos 4x-{{\sin }^{2}}2x+\cos 2x-2=0$
A. $\left[ \begin{array}{l}x=\frac{\pi }{2}+k2\pi \\x=\pm \arccos \frac{6}{7}+k2\pi \end{array} \right.(k\in Z)$
B. $\left[ \begin{array}{l}x=\frac{\pi }{2}+k\frac{\pi }{2}\\x=\pm \arccos \frac{6}{7}+k2\pi \end{array} \right.(k\in Z)$
C. $\left[ \begin{array}{l}x=\frac{\pi }{2}+k\pi \\x=\pm \arccos \frac{6}{7}+k\pi \end{array} \right.(k\in Z)$
D. $\left[ \begin{array}{l}x=\frac{\pi }{2}+k\pi \\x=\pm \frac{1}{2}\arccos \frac{6}{7}+k\pi \end{array} \right.(k\in \mathbb{Z})$

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