Giải phương trình $\sqrt{3}\sin 2x-\cos 2x+1=0$
A. $\left[ \begin{array}{l}x=k\pi \\x=\frac{\pi }{3}+k\pi \end{array} \right.$
B. $\left[ \begin{array}{l}x=k\pi \\x=\frac{{2\pi }}{3}+k2\pi \end{array} \right.$
C. $\left[ \begin{array}{l}x=2k\pi \\x=\frac{{2\pi }}{3}+k2\pi \end{array} \right.$
D. $\left[ \begin{array}{l}x=k\pi \\x=\frac{{2\pi }}{3}+k\pi \end{array} \right.$
A. $\left[ \begin{array}{l}x=k\pi \\x=\frac{\pi }{3}+k\pi \end{array} \right.$
B. $\left[ \begin{array}{l}x=k\pi \\x=\frac{{2\pi }}{3}+k2\pi \end{array} \right.$
C. $\left[ \begin{array}{l}x=2k\pi \\x=\frac{{2\pi }}{3}+k2\pi \end{array} \right.$
D. $\left[ \begin{array}{l}x=k\pi \\x=\frac{{2\pi }}{3}+k\pi \end{array} \right.$
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Hóa Học lớp 12
