Đáp án:
Giải thích các bước giải:
$\dfrac{x-5}{x-1}+\dfrac{2}{x-3}=1$
$ $
$⇔\dfrac{(x-5).(x-3)}{(x-1).(x-3)}+\dfrac{2.(x-1)}{(x-3).(x-1)}=\dfrac{(x-1).(x-3)}{(x-1).(x-3)}$
$ $
$⇔(x-5).(x-3)+2.(x-1)=(x-1).(x-3)$
$⇔x.(x-5)-3.(x-5)+2x-2=x.(x-1)-3.(x-1)$
$⇔x^{2}-5x-3x+15+2x-2=x^{2}-x-3x+3$
$⇔x^{2}-6x+13=x^{2}-4x+3$
$⇔-2x=-10$
$⇔x=5$