Giải phương trình: \(\dfrac{4}{{{{\cos }^2}x}} + \tan x = 7.\)
A.\(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k\pi \\x = -\arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
B.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{4} + k\pi \\x =-\arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
C.\(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k\pi \\x = \arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
D.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{4} + k\pi \\x = \arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
A.\(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k\pi \\x = -\arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
B.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{4} + k\pi \\x =-\arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
C.\(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k\pi \\x = \arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
D.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{4} + k\pi \\x = \arctan \left( {\dfrac{3}{4}} \right) + k\pi \end{array} \right.\)
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Hóa Học lớp 12
