(x+1)$^{2}$-$x^{2}$+8$x$-16=0
⇔$x^{2}$+2$x$+1-$x^{2}$ +8$x$-16=0
⇔10$x$-15=0
⇔$x$=$\frac{3}{2}$
($x$+1)($x$-1)$^{2}$-($x$+1)($x$-2)$^{2}$=0
⇔($x$+1) [($x$-1)$^{2}$-($x$-2)$^{2}$]=0
⇔\(\left[ \begin{array}{l}x+1=0\\(x-1)^{2}-(x-2)^2=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=1\\x=\frac{3}{2}\end{array} \right.\)
