Giải thích các bước giải:
1) 3x(2x-1)-2x+1=0
⇔ 3x(2x-1)-(2x-1)=0
⇔ (2x-1)(3x-1)=0
⇔ \(\left[ \begin{array}{l}2x-1=0\\3x-1=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=1/2\\x=1/3\end{array} \right.\)
Vậy S={1/2;1/3}
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2) 2x(x-5)-3x+15=0
⇔ 2x(x-5)-3(x-5)=0
⇔ (x-5)(2x-3)=0
⇔ \(\left[ \begin{array}{l}x-5=0\\2x-3=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=5\\x=3/2\end{array} \right.\)
Vậy S={5;3/2}
