Đáp án:
`1`⎣⎢⎢⎡x=0x=1x=−2x=−3
`2`⎣⎢⎢⎢⎢⎡x=0x=23x=1x=2−1
Giải thích các bước giải:
`1, (x+1)^2-3|x+1|+2=0`
`<=> x^2+2x+1-3|x+1|+2=0`
`<=> x^2+2x+3=3|x+1|`
`<=>`[3(x+1)=x2+2x+33(x+1)=−x2−2x−3
`<=>`[x2−x=0x2+5x+6=0
`<=>`[x(x−1)=0(x+2)(x+3)=0
`<=>`⎣⎢⎢⎡x=0x=1x=−2x=−3
`2, 4x(x-1)=|2x-1|+1`
`<=> 4x^2-4x-1=|2x-1|`
`<=>`[2x−1=4x2−4x−12x−1=−4x2+4x+1
`<=>`[4x2−6x=04x2−2x−2=0
`<=>`[2x(2x−3)=02(x−1)(2x+1)=0
`<=>`⎣⎢⎢⎢⎢⎡x=0x=23x=1x=2−1