Đáp án:
`\text{Em tham khảo!}`
Giải thích các bước giải:
`a,2(4-2x)-1=x-3`
`=>8-4x-1=x-3`
`=>7-4x=x-3`
`=>5x-10=0`
`=>x-2=0`
`=>x=2`
`b,(2x-1)(x^2-6)=0`
`=>` \(\left[ \begin{array}{l}2x=1\\x^2=6\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=-\sqrt{6}\\x=\sqrt{6}\end{array} \right.\)
`c,(x+2)(5-4x)=(x+2)^2`
`=>(x+2)(5-4x-x-2)=0`
`=>(x+2)(3-5x)=0`
`=>` \(\left[ \begin{array}{l}x=-2\\x=\dfrac{3}{5}\end{array} \right.\)