Giải phương trình và hệ phương trình sau:
a) \(2{x^2} - 3x - 2 = 0 \)
b) \( \left \{ \begin{array}{l}2x - 3y = 12 \ \3x + y = 7 \end{array} \right. \)
A.\(\begin{array}{l}a)\,S = \left\{ { - \frac{1}{2};\,2} \right\}\\b)\,\left( {x;\,y} \right) = \left( {3;\, - 2} \right)\end{array}\)
B.\(\begin{array}{l}a)\,S = \left\{ { - \frac{1}{2};\, - 2} \right\}\\b)\,\left( {x;\,y} \right) = \left( {3;\, - 2} \right)\end{array}\)
C.\(\begin{array}{l}a)\,S = \left\{ { - \frac{1}{2};\,2} \right\}\\b)\,\left( {x;\,y} \right) = \left( {3;\,2} \right)\end{array}\)
D.\(\begin{array}{l}a)\,S = \left\{ { - \frac{1}{2};\, - 2} \right\}\\b)\,\left( {x;\,y} \right) = \left( {3;\,2} \right)\end{array}\)